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Last updated on September 15, 2025

Derivative of (cos x)^2

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We use the derivative of (cos x)^2 to understand how the function changes in response to a slight change in x. Derivatives help us calculate rates of change in real-life situations. We will now explore the derivative of (cos x)^2 in detail.

Derivative of (cos x)^2 for US Students
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What is the Derivative of (cos x)^2?

We now explore the derivative of (cos x)^2. It is commonly represented as d/dx ((cos x)^2) or ((cos x)^2)', and its value is -2cos(x)sin(x). The function (cos x)^2 has a clearly defined derivative, indicating it is differentiable within its domain. The key concepts are mentioned below:

 

Cosine Function: (cos(x) is a trigonometric function).

 

Power Rule: Rule for differentiating functions in the form of a power.

 

Sine Function: sin(x) is another fundamental trigonometric function.

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Derivative of (cos x)^2 Formula

The derivative of (cos x)^2 can be denoted as d/dx ((cos x)^2) or ((cos x)^2)'.

 

The formula we use to differentiate (cos x)^2 is: d/dx ((cos x)^2) = -2cos(x)sin(x)

 

The formula applies to all x where the function is defined.

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Proofs of the Derivative of (cos x)^2

We can derive the derivative of (cos x)^2 using proofs. To show this, we will use trigonometric identities along with the rules of differentiation. There are several methods we use to prove this, such as:

 

  1. By First Principle
  2. Using Chain Rule
  3. Using Product Rule

 

We will now demonstrate that the differentiation of (cos x)^2 results in -2cos(x)sin(x) using the above-mentioned methods:

 

By First Principle

 

The derivative of (cos x)^2 can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient.

 

To find the derivative of (cos x)^2 using the first principle, we will consider f(x) = (cos x)^2. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1)

 

Given that f(x) = (cos x)^2, we write f(x + h) = (cos (x + h))^2.

 

Substituting these into equation (1), f'(x) = limₕ→₀ [(cos(x + h))^2 - (cos x)^2] / h

 

Using trigonometric identities and simplifying, f'(x) = limₕ→₀ [-sin(2x + 2h) + sin(2x)] / 2h As h approaches zero, this simplifies to: f'(x) = -2cos(x)sin(x)

 

Hence, proved.

 

Using Chain Rule

 

To prove the differentiation of (cos x)^2 using the chain rule, Let u = cos x, then (cos x)^2 = u^2. Using the chain rule, d/dx(u^2) = 2u * du/dx. The derivative of cos x is -sin x, so du/dx = -sin x.

 

Substituting back, we get: d/dx((cos x)^2) = 2cos(x)(-sin(x)) = -2cos(x)sin(x).

 

Using Product Rule

 

We will now prove the derivative of (cos x)^2 using the product rule. The step-by-step process is demonstrated below: Here, we express (cos x)^2 as (cos x)(cos x). Let u = cos x and v = cos x.

 

Using the product rule formula: d/dx [u.v] = u'. v + u. v' u' = d/dx (cos x) = -sin x v' = d/dx (cos x) = -sin x

 

Now apply the product rule: d/dx((cos x)^2) = (cos x)(-sin x) + (cos x)(-sin x) = -2cos(x)sin(x)

 

Thus, the derivative is -2cos(x)sin(x).

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Higher-Order Derivatives of (cos x)^2

When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.

 

To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like (cos x)^2.

 

For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues.

 

For the nth Derivative of (cos x)^2, we generally use fⁿ(x) for the nth derivative of a function f(x) which tells us the change in the rate of change. (continuing for higher-order derivatives).

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Special Cases:

When x is an integer multiple of π, the derivative is zero because sin(x) is zero at these points. When x is π/2 or 3π/2, the value of the derivative is non-zero because cos(x) is zero.

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Common Mistakes and How to Avoid Them in Derivatives of (cos x)^2

Students frequently make mistakes when differentiating (cos x)^2. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:

Mistake 1

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Not applying the Chain Rule

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Students may forget to apply the chain rule properly, which can lead to incorrect results. They often skip steps and directly arrive at the result, especially when dealing with composite functions. Ensure that each step is written in order. Students might think it is awkward, but it is important to avoid errors in the process.

Mistake 2

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Incorrect use of Product Rule

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While differentiating functions such as (cos x)^2, students misapply the product rule. For example: Incorrect differentiation: d/dx ((cos x)^2) = 2cos(x). To avoid this mistake, write the product rule without errors. Always check for errors in the calculation and ensure it is properly simplified.

Mistake 3

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Forgetting the Negative Sign

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There is a common mistake that students at times forget the negative sign when differentiating cosine functions. For example, they incorrectly write d/dx (cos x)^2 = 2cos(x)sin(x). Students should check the signs in the terms and ensure they are applied properly. For example, d/dx ((cos x)^2) = -2cos(x)sin(x).

Mistake 4

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Overlooking Trigonometric Identities

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Students often overlook trigonometric identities that can simplify the differentiation process. For instance, not recognizing that sin(2x) = 2sin(x)cos(x) can lead to more complicated expressions. Always look for opportunities to simplify using identities.

Mistake 5

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Not Checking the Domain

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Students may forget to consider the domain of the function, especially when dealing with trigonometric functions. Remember that the derivative is only valid where the original function is defined.

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Examples Using the Derivative of (cos x)^2

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Problem 1

Calculate the derivative of ((cos x)^2) · sin(x).

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Here, we have f(x) = ((cos x)^2) · sin(x).

 

Using the product rule, f'(x) = u′v + uv′ In the given equation, u = (cos x)^2 and v = sin(x).

 

Let’s differentiate each term, u′= d/dx ((cos x)^2) = -2cos(x)sin(x) v′= d/dx (sin x) = cos(x)

 

Substituting into the given equation, f'(x) = (-2cos(x)sin(x))(sin(x)) + ((cos x)^2)(cos(x))

 

Let’s simplify terms to get the final answer, f'(x) = -2cos(x)(sin^2(x)) + (cos^3(x))

 

Thus, the derivative of the specified function is -2cos(x)(sin^2(x)) + (cos^3(x)).

Explanation

We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.

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Problem 2

A physics experiment requires analyzing a wave function represented by y = (cos(x))^2. If x = π/4, find the rate of change of the wave function.

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We have y = (cos(x))^2...(1)

 

Now, we will differentiate the equation (1) Take the derivative: dy/dx = -2cos(x)sin(x)

 

Given x = π/4, substitute this into the derivative: dy/dx = -2cos(π/4)sin(π/4) = -2(√2/2)(√2/2) = -1

 

Hence, we get the rate of change of the wave function at x = π/4 as -1.

Explanation

We find the rate of change of the wave function at x = π/4 as -1, which indicates the wave is decreasing at that point.

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Problem 3

Derive the second derivative of the function y = (cos(x))^2.

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The first step is to find the first derivative, dy/dx = -2cos(x)sin(x)...(1)

 

Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [-2cos(x)sin(x)]

 

Using the product rule, d²y/dx² = -2(d/dx[cos(x)]sin(x) + cos(x)d/dx[sin(x)]) = -2[-sin(x)sin(x) + cos(x)cos(x)] = -2[-sin²(x) + cos²(x)]

 

Therefore, the second derivative of the function y = (cos(x))^2 is -2[cos(2x)].

Explanation

We use the step-by-step process, where we start with the first derivative. Using the product rule, we differentiate the product -2cos(x)sin(x). We then simplify the terms to find the final answer.

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Problem 4

Prove: d/dx ((cos x)^3) = -3cos^2(x)sin(x).

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Let’s start using the chain rule: Consider y = (cos x)^3

 

To differentiate, we use the chain rule: dy/dx = 3(cos x)^2 * d/dx[cos x]

 

Since the derivative of cos(x) is -sin(x), dy/dx = 3(cos x)^2 * (-sin(x)) dy/dx = -3cos^2(x)sin(x)

 

Hence proved.

Explanation

In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replace cos(x) with its derivative. As a final step, we substitute y = (cos x)^3 to derive the equation.

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Problem 5

Solve: d/dx ((cos x)^2/x)

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To differentiate the function, we use the quotient rule: d/dx ((cos x)^2/x) = (d/dx ((cos x)^2) * x - (cos x)^2 * d/dx(x))/x²

 

We will substitute d/dx ((cos x)^2) = -2cos(x)sin(x) and d/dx(x) = 1 = (-2cos(x)sin(x) * x - (cos x)^2)/x² = (-2xcos(x)sin(x) - (cos x)^2)/x²

 

Therefore, d/dx ((cos x)^2/x) = (-2xcos(x)sin(x) - (cos x)^2)/x²

Explanation

In this process, we differentiate the given function using the quotient rule. As a final step, we simplify the equation to obtain the final result.

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FAQs on the Derivative of (cos x)^2

1.Find the derivative of (cos x)^2.

Using the chain rule on (cos x)^2 gives: d/dx ((cos x)^2) = -2cos(x)sin(x).

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2.Can we use the derivative of (cos x)^2 in real life?

Yes, we can use the derivative of (cos x)^2 in real life in calculating rates of change in fields such as physics and engineering.

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3.Is it possible to take the derivative of (cos x)^2 at the point where x = π/2?

Yes, the derivative is zero at x = π/2 because cos(x) is zero, and thus the rate of change is zero.

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4.What rule is used to differentiate (cos x)^2/x?

We use the quotient rule to differentiate (cos x)^2/x: d/dx ((cos x)^2/x) = (-2xcos(x)sin(x) - (cos x)^2)/x².

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5.Are the derivatives of (cos x)^2 and (cos x)³ the same?

No, they are different. The derivative of (cos x)^2 is -2cos(x)sin(x), while the derivative of (cos x)³ is -3cos²(x)sin(x).

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Important Glossaries for the Derivative of (cos x)^2

  • Derivative: The derivative of a function indicates how the given function changes in response to a slight change in x.

 

  • Cosine Function: A trigonometric function that represents the adjacent side over the hypotenuse in a right triangle.

 

  • Sine Function: A trigonometric function that represents the opposite side over the hypotenuse in a right triangle.

 

  • Chain Rule: A formula for computing the derivative of the composition of two or more functions.

 

  • Product Rule: A formula used to find the derivatives of products of two or more functions.
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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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