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Last updated on September 15, 2025
We use the derivative of (cos x)^2 to understand how the function changes in response to a slight change in x. Derivatives help us calculate rates of change in real-life situations. We will now explore the derivative of (cos x)^2 in detail.
We now explore the derivative of (cos x)^2. It is commonly represented as d/dx ((cos x)^2) or ((cos x)^2)', and its value is -2cos(x)sin(x). The function (cos x)^2 has a clearly defined derivative, indicating it is differentiable within its domain. The key concepts are mentioned below:
Cosine Function: (cos(x) is a trigonometric function).
Power Rule: Rule for differentiating functions in the form of a power.
Sine Function: sin(x) is another fundamental trigonometric function.
The derivative of (cos x)^2 can be denoted as d/dx ((cos x)^2) or ((cos x)^2)'.
The formula we use to differentiate (cos x)^2 is: d/dx ((cos x)^2) = -2cos(x)sin(x)
The formula applies to all x where the function is defined.
We can derive the derivative of (cos x)^2 using proofs. To show this, we will use trigonometric identities along with the rules of differentiation. There are several methods we use to prove this, such as:
We will now demonstrate that the differentiation of (cos x)^2 results in -2cos(x)sin(x) using the above-mentioned methods:
The derivative of (cos x)^2 can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient.
To find the derivative of (cos x)^2 using the first principle, we will consider f(x) = (cos x)^2. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1)
Given that f(x) = (cos x)^2, we write f(x + h) = (cos (x + h))^2.
Substituting these into equation (1), f'(x) = limₕ→₀ [(cos(x + h))^2 - (cos x)^2] / h
Using trigonometric identities and simplifying, f'(x) = limₕ→₀ [-sin(2x + 2h) + sin(2x)] / 2h As h approaches zero, this simplifies to: f'(x) = -2cos(x)sin(x)
Hence, proved.
To prove the differentiation of (cos x)^2 using the chain rule, Let u = cos x, then (cos x)^2 = u^2. Using the chain rule, d/dx(u^2) = 2u * du/dx. The derivative of cos x is -sin x, so du/dx = -sin x.
Substituting back, we get: d/dx((cos x)^2) = 2cos(x)(-sin(x)) = -2cos(x)sin(x).
We will now prove the derivative of (cos x)^2 using the product rule. The step-by-step process is demonstrated below: Here, we express (cos x)^2 as (cos x)(cos x). Let u = cos x and v = cos x.
Using the product rule formula: d/dx [u.v] = u'. v + u. v' u' = d/dx (cos x) = -sin x v' = d/dx (cos x) = -sin x
Now apply the product rule: d/dx((cos x)^2) = (cos x)(-sin x) + (cos x)(-sin x) = -2cos(x)sin(x)
Thus, the derivative is -2cos(x)sin(x).
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.
To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like (cos x)^2.
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues.
For the nth Derivative of (cos x)^2, we generally use fⁿ(x) for the nth derivative of a function f(x) which tells us the change in the rate of change. (continuing for higher-order derivatives).
When x is an integer multiple of π, the derivative is zero because sin(x) is zero at these points. When x is π/2 or 3π/2, the value of the derivative is non-zero because cos(x) is zero.
Students frequently make mistakes when differentiating (cos x)^2. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of ((cos x)^2) · sin(x).
Here, we have f(x) = ((cos x)^2) · sin(x).
Using the product rule, f'(x) = u′v + uv′ In the given equation, u = (cos x)^2 and v = sin(x).
Let’s differentiate each term, u′= d/dx ((cos x)^2) = -2cos(x)sin(x) v′= d/dx (sin x) = cos(x)
Substituting into the given equation, f'(x) = (-2cos(x)sin(x))(sin(x)) + ((cos x)^2)(cos(x))
Let’s simplify terms to get the final answer, f'(x) = -2cos(x)(sin^2(x)) + (cos^3(x))
Thus, the derivative of the specified function is -2cos(x)(sin^2(x)) + (cos^3(x)).
We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.
A physics experiment requires analyzing a wave function represented by y = (cos(x))^2. If x = π/4, find the rate of change of the wave function.
We have y = (cos(x))^2...(1)
Now, we will differentiate the equation (1) Take the derivative: dy/dx = -2cos(x)sin(x)
Given x = π/4, substitute this into the derivative: dy/dx = -2cos(π/4)sin(π/4) = -2(√2/2)(√2/2) = -1
Hence, we get the rate of change of the wave function at x = π/4 as -1.
We find the rate of change of the wave function at x = π/4 as -1, which indicates the wave is decreasing at that point.
Derive the second derivative of the function y = (cos(x))^2.
The first step is to find the first derivative, dy/dx = -2cos(x)sin(x)...(1)
Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [-2cos(x)sin(x)]
Using the product rule, d²y/dx² = -2(d/dx[cos(x)]sin(x) + cos(x)d/dx[sin(x)]) = -2[-sin(x)sin(x) + cos(x)cos(x)] = -2[-sin²(x) + cos²(x)]
Therefore, the second derivative of the function y = (cos(x))^2 is -2[cos(2x)].
We use the step-by-step process, where we start with the first derivative. Using the product rule, we differentiate the product -2cos(x)sin(x). We then simplify the terms to find the final answer.
Prove: d/dx ((cos x)^3) = -3cos^2(x)sin(x).
Let’s start using the chain rule: Consider y = (cos x)^3
To differentiate, we use the chain rule: dy/dx = 3(cos x)^2 * d/dx[cos x]
Since the derivative of cos(x) is -sin(x), dy/dx = 3(cos x)^2 * (-sin(x)) dy/dx = -3cos^2(x)sin(x)
Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replace cos(x) with its derivative. As a final step, we substitute y = (cos x)^3 to derive the equation.
Solve: d/dx ((cos x)^2/x)
To differentiate the function, we use the quotient rule: d/dx ((cos x)^2/x) = (d/dx ((cos x)^2) * x - (cos x)^2 * d/dx(x))/x²
We will substitute d/dx ((cos x)^2) = -2cos(x)sin(x) and d/dx(x) = 1 = (-2cos(x)sin(x) * x - (cos x)^2)/x² = (-2xcos(x)sin(x) - (cos x)^2)/x²
Therefore, d/dx ((cos x)^2/x) = (-2xcos(x)sin(x) - (cos x)^2)/x²
In this process, we differentiate the given function using the quotient rule. As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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